(1) f(x)=x^3+ax^2+bå¨x=1å¤çæå¼=-1, 两å±ææ
1. f'(x)=3x^2+2ax, f'(1)=3+2a=0
2. f(1)=1+a+b=-1
解æ¤äºå¼ç»æçæ¹ç¨ç» å¾ a=-3/2, b=-1/2
(2)ç±(1)ç¥ f(x)=x^3-3x^2/2-1/2
f'(x)=3x^2-3x 令3x^2-3x>0, å¾x<0æx>1, å³å¨æ¤èå´f(x)æ¯éå¢ç
åç令3x^2-3x<0,å¾0<x<1, å¨æ¤èå´å
f(x)æ¯éåç
æ以å½x=0æ¶, f(x)çæ大å¼=f(0)=-1/2
å½x=1æ¶,f(x)çæå°å¼=f(1)=-1
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