如题所述
答案为y(1-x)/x(y-1),e^(x+y)怎么没了?
因为e^(x+y)=xy可以继续化简(e^(x+y)-y)/(x-e^(x+y)) =(xy-y)/(x-xy)=y(1-x)/x(y-1)写(e^(x+y)-y)/(x-e^(x+y)) 也是对的明白了么
e^(x+y)怎么会等于xy,是求导?还是?求完整解答~~~
xy=e^(x+y)就是已知条件啊是x,y满足的函数关系(e^(x+y)-y)/(x-e^(x+y)) 也是对的