ç±å·²ç¥ï¼æ
a=log18(9)=log2(9)/log2(18)=2log2(3)/[1+2log2(3)]
b=log18(5)=log2(5)/log2(18)=log2(5)/[1+2log2(3)]
ç±æ¤è§£å¾ log2(3)=a/[2(1-a)]ï¼log2(5)=b/(1-a)ï¼
æ以ï¼æ ¹æ®å¯¹æ°æ¢åºå
¬å¼å¾
log36(5)=log2(5)/log2(36)=log2(5)/[2+2log2(3)]=b/(2+a)ã
温馨提示:答案为网友推荐,仅供参考