已知函数f x等于cos方x加cos方(x+π/3 )求f x最小正周期

如题所述

f(x) = cos²x + cos²(x+π/3 )
= 1/2cos(2x)+1/2 + 1/2cos(2x+2π/3) +1/2
= 1/2{ cos2x+cos(2x+2π/3) } +1
= 1/2{ cos2x+cos2xcos2π/3-sin2xsin2π/3 } +1
= 1/2{ cos2x-1/2cos2x-√3/2sin2x } +1
= 1/2{ 1/2cos2x-√3/2sin2x } +1
= 1/2{ cos2xcosπ/3-sin2xsinπ/3 } +1
= 1/2cos(2x+π/3) + 1
最小正周期 T = 2π/2 = π
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第1个回答  2016-01-20

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