如题所述
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解ï¼
(x²+3x-3)(x²+3x+4)-8=(x²+3x)²+(x²+3x)-12-8=(x²+3x)²+(x²+3x)-20=(x²+3x+5)(x²+3x-4)
=(x²+3x+5)(x+4)(x-1)
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