设f（x）可导，求下列函数的导数与微分 如图 只需做7.的（3）（5）题

Question

如题所述

Answer 1

(5)
y=f(1-2x)+ sin[f(x)]
y' = -2f'(1-2x) + f'(x).cos[f(x)]
(3)
y=e^{[f(x)]^2}
y' = e^{[f(x)]^2} . ( 2f(x) ) . f'(x)
= 2f(x).f'(x) e^{[f(x)]^2}
dy =[2f(x).f'(x) e^{[f(x)]^2}] dx
(5)
y=f(1-2x)+ sin[f(x)]
y' = -2f'(1-2x) + f'(x).cos[f(x)]
dy ={-2f'(1-2x) + f'(x).cos[f(x)] } dx本回答被提问者采纳