ï¼1ï¼
T=2Ï/w=Ï
解å¾w=2
f(x)=â3cos2x
f(a)=â3cos2a=â6/2
cos2a=â2/2 2aâ[-2Ïï¼2Ï]
2a=±Ï/4æ2a=±7Ï/4
解å¾
a=±Ï/8æa=±7Ï/8
ï¼2ï¼
y=â3cos2x+sin(2x-Ï/3)
=â3cos2x+sin2xcosÏ/3-cos2xsinÏ/3
=â3cos2x+1/2 sin2x-â3/2 cos2x
=1/2 sin2x+â3/2 cos2x
=sin2xcosÏ/3+cos2x sinÏ/3
=sin(2x+Ï/3)
令-Ï/2+2kÏâ¤2x+Ï/3â¤Ï/2+2kÏå¾
-5Ï/6+2kÏâ¤2xâ¤Ï/6+2kÏ
-5Ï/12+kÏâ¤xâ¤Ï/12+kÏ
æ以åè°å¢åºé´ä¸º[-5Ï/12+kÏï¼Ï/12+kÏ] ï¼kâZï¼
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