y=x,y=x²,解得x=0,y=0或x=1,y=0
y=2x,y=x²,解得x=0,y=0或x=2,y=2
先对x积分,再对y积分,y的积分区间分成两段(0,1),(1,2)
∫(0,1)∫(y/2,y)dxdy
=∫(0,1)(y/2)dy
=[y²/4](0,1)
=1/4
∫(1,2)∫(y/2,根号y)dxdy
=∫(1,2)(根号y-y/2)
=[(2/3)y^(3/2)-y²/4](1,2)
=[(2/3)×2^(3/2)-2²/4]-[(2/3)-(1/4)]
=[4(根号2)/3]-(17/12)
所求面积=(1/4)+[4(根号2)/3]-(17/12)=[4(根号2)/3]-(7/6)
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