æ ¹æ®ä¸¤ç¹å¼ï¼
(y-0)/(x+2) = (y+1)/(x+1)
xy+x+2y+2=xy+y
x+y+2=0
ç´çº¿ç解æå¼y=-x-2
å°ï¼-1ï¼-1ï¼ä»£å
¥y=ax^2
a=-1
æç©çº¿è§£æå¼ï¼y=-x^2
å°y=-x-2代å
¥y=-x^2
x^2-x-2=0
(x+1)(x-2)=0
Cç¹ç横åæ x=2ï¼y=-2-2=-4
C(2,-4)
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