根号下cot二分之x求导怎么做

Question

如题所述

Answer 1

根号下cot二分之x求导
=(√cot(x/2) )'
=1/2*[cot(x/2)]^(-1/2)*[-1/sin²(x/2)]*(1/2)
=-(1/4)*[cot(x/2)]^(-1/2)*[1/sin²(x/2)]