xy=e^x+y
两边同时对x求导
y+x(dx/dy)=e^x+(dx/dy)
y+xy'=e^x+y'
xy'-y'=e^x-y
(x-1)y'=e^x-y
y'=(e^x-y)/(x-1)
我的不对?难道你是xy=e^(x+y)?要是的话,求解如下:
y+xy'=e^(x+y)*(x+y)'
y+xy'=e^(x+y)*(1+y')
y+xy'=e^(x+y)+y'*e^(x+y)
(x-e^(x+y))y'=e^(x+y)-y
y'=(e^(x+y)-y)/(x-e^(x+y))
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