C++程序。输入一个字符,如果为字母,则输出其ASCII码

Question

呃。。不能用WHILE。。我们还没学到那了- -

Answer 1

#include<iostream>
using namespace std;
int main()
{
char ch;
while(cout<<"Enter one Character(ctrl+z to end):"<<endl&&cin>>ch)
{
if(ch>='a'&&ch<='z'||ch>='A'&&ch<='Z')
cout<<"ASCII:"<<static_cast<int>(ch)<<endl;
}
return 0;
}

//标准的C++程序
//static_cast<int>(ch)是C++中的强制类型转换

//以下针对修改程序
#include<iostream>
using namespace std;
int main()
{
char ch;
cout<<"Enter one Character:"<<endl;
cin>>ch;
if(ch>='a'&&ch<='z'||ch>='A'&&ch<='Z')
cout<<"ASCII:"<<static_cast<int>(ch)<<endl;
return 0;
}

Answer 2

#include <iostream>
using namespace std;
int main()
{
char ch;
cout << "请输入一个字符：" << endl;
cin >> ch;
if (ch >= 'a' && ch <= 'z' || ch >= 'A' && ch <= 'Z' || ch >= '0' && ch <= '9')
{
cout << "输入的字符" << ch << "所对应的ASCII码值为：" << int(ch) << endl;
}
else
{
cout << "输入有误！" << endl;
}
return 0;
}

Answer 3

#include <iostream>
#include <cctype>

using namespace std;

int main() {
    char c;
    while (cin >> c) {
        if (isalpha(c)) {
            cout << (int) c << endl;
        }
    }
}

Answer 4

char d;
int a;
if(d>='a'&&d<='z')
a=(int)d;
输出a；