这个c语言（c＋＋）的程序要怎么写？

Question

内容：设计一个猜数字游戏，它能根据游戏规则猜数。
功能：产生原始数字：产生4个随机数，并按任意顺序排列。
游戏提示：用1A2B形式提示玩家当前猜数字的匹配情况。例如1A表示玩家猜测的数字有1个与系统产生的原始数字符合，并且位置也符合。2B表示玩家猜测的数字有2个与系统产生的原始数字符合，但位置不符合。
原始数字显示：当用户10次仍然不能猜出正确的原始数字和顺序时，系统提示玩家失败，并给玩家显示原始数字和顺序。
提示：可能涉及语法点：数组、选择与循环、函数

完全不明白要怎么出随机排序还要对号，如果有高人能编写出完整的可运行的程序，我会再追加分数！
当用户10次仍然不能猜出正确的原始数字和顺序时，系统提示玩家失败，并给玩家显示原始数字和顺序。
这点好像没有达到啊！不过强人，做到这里已经非常感谢了

我需要的程序代码是能直接复制在Microsoft visual c++6.0中即可运行出结果的

Answer 1

#include <stdio.h>
#include <stdlib.h>
#include <time.h>

void RandomShuffle(int* a, int n)
{
int tmp, i, pick;

for(i = 0; i < n; ++i)
{
pick = rand() % n;
tmp = a[i];
a[i] = a[pick];
a[pick] = tmp;
}
}

void PrintSeq(int* beg, int* end)
{
while(beg != end)
printf("%d ", *beg++);
putchar('\n');
}

void ReadSeq(int* beg, int* end)
{
while(beg != end)
scanf("%d", beg++);
}

int Analyse(int* resBeg, int* resEnd, int* beg, int* end)
{
int fully_match = 0;
int numbers_match = 0;
int* p1, * p2;

for(p1 = beg; p1 != end; ++p1)
for(p2 = resBeg; p2 != resEnd; ++p2)
{
if(*p2 == *p1 && p2 - resBeg == p1 - beg)
++fully_match;
else if(*p2 == *p1)
++numbers_match;
}

if(fully_match != end - beg)
return printf("Clue: %dA%dB\n", fully_match, numbers_match), 0;
else
return 1;
}

void Guess(int* resBeg, int* resEnd, int allowedTimes)
{
int* myNumBeg = (int*)malloc(sizeof(int) * (resEnd - resBeg));
int* myNumEnd = myNumBeg + (resEnd - resBeg);

printf("NOTE: No Duplicates!\n");

do{
printf("\nEnter %d numbers(You have %d more chance):\n", myNumEnd - myNumBeg, allowedTimes);
ReadSeq(myNumBeg, myNumEnd);
}while(!Analyse(resBeg, resEnd, myNumBeg, myNumEnd) && --allowedTimes > 0);

if(allowedTimes != 0)
printf("\nYou got it!\n");
else
printf("\nGame Over!!\n");

printf("Origin seq is: ");
PrintSeq(resBeg, resEnd);

free(myNumBeg);
}

int main()
{
srand((unsigned)time(0));

int a[] = {0, 1, 2, 3, 4, 5, 6, 7, 8, 9};

RandomShuffle(a, 10); // 随机打乱
Guess(a, a + 4, 10); // 选4个数字作为答案，允许用户猜10次
return 0;
}

有失败提示和给出答案结果的过程啊，以下是(3次机会)我在vc6.0的测试:

NOTE: No Duplicates!

Enter 4 numbers(You have 3 more chance): // 第一次
1 2 3 4
Clue: 1A0B

Enter 4 numbers(You have 2 more chance): // 第二次
2 3 1 4
Clue: 0A1B

Enter 4 numbers(You have 1 more chance): // 第三次
1 2 4 3
Clue: 1A0B

Game Over!! // 没猜着，猜着的话是You got it!
Origin seq is: 0 2 9 7 // 答案(原始数组)
Press any key to continue

Answer 2

以下是主要代码
这个程序是个Win32窗口程序，如果要完整工程源代码请给我你的电子邮箱地址

我的:[e-mail]

// GuessNum.cpp
//
//GuessNum App
//SigmaTera
//2007-08-14

#include "stdafx.h"
#include "resource.h"

#include <ctime>
#include <cstdlib>

void GenerateNum(LPTSTR lpDights,int nLength);
void CheckInputNum(LPCTSTR lpDigits,LPCTSTR lpGenDigits,LPTSTR lpResult,int nLenDigits,int nLenResult);
bool CheckInput(LPCTSTR lpDigits);

BOOL WINAPI DlgProc(HWND hWnd,UINT uMsg,WPARAM wParam,LPARAM lParam);

int APIENTRY WinMain(HINSTANCE hInstance,
HINSTANCE hPrevInstance,
LPSTR lpCmdLine,
int nCmdShow)
{
// TODO: Place code here.
DialogBoxParam(hInstance,MAKEINTRESOURCE(IDD_DIALOG_MAIN),NULL,DlgProc,0);
return 0;
}
BOOL WINAPI DlgProc(HWND hWnd,UINT uMsg,WPARAM wParam,LPARAM lParam)
{
static TCHAR szDigit[5];
static TCHAR szResult[5];
static TCHAR szInputDigits[5];
static TCHAR szTips[16];

static int nTimes = 10;

if (uMsg == WM_INITDIALOG)
{
EnableWindow(GetDlgItem(hWnd,IDOK),FALSE);
SetWindowText(GetDlgItem(hWnd,IDC_TIPS),"祝您成功!");
}
else if (uMsg == WM_CLOSE)
{
EndDialog(hWnd,0);
}
else if (uMsg == WM_COMMAND)
{
switch(LOWORD(wParam))
{
case IDGEN:
GenerateNum(szDigit,4);
EnableWindow(GetDlgItem(hWnd,IDOK),TRUE);
nTimes = 10;
break;
case IDOK:
GetWindowText(GetDlgItem(hWnd,IDC_EDIT_INP),szInputDigits,5);
if (lstrlen(szInputDigits) < 4 || CheckInput(szInputDigits) == false)
{
MessageBox(0,"输入非法","提示",MB_OK);
SetWindowText(GetDlgItem(hWnd,IDC_EDIT_INP),"");
break;
}

CheckInputNum(szDigit,szInputDigits,szResult,4,4);
SetWindowText(GetDlgItem(hWnd,IDC_SHOW_RESULT),szResult);
if (lstrcmp(szInputDigits,szDigit) == 0)
{
MessageBox(0,"恭喜您猜对了!","提示",0);
EnableWindow(GetDlgItem(hWnd,IDOK),FALSE);
}
nTimes--;
wsprintf(szTips,"您还有%d次机会",nTimes);
if (nTimes == 0)
{
SetWindowText(GetDlgItem(hWnd,IDC_TIPS),"失败了:(");
MessageBox(0,"抱歉，您在10次内没有答对","提示",0);
EnableWindow(GetDlgItem(hWnd,IDOK),FALSE);
break;
}
SetWindowText(GetDlgItem(hWnd,IDC_TIPS),szTips);
break;
case IDCANCEL:
EndDialog(hWnd,0);
break;
}
}
return FALSE;
}

void GenerateNum(LPTSTR lpDights,int nLength)
{
srand(time(0));
int i = 0;
int nGen = 0;
bool bGenerated = false;

while(i < nLength)
{
bGenerated = false;
nGen = rand() % 10 + 48;
for (int j = i;j >= 0;j--)
{
if (lpDights[j] == nGen)
{
bGenerated = true;
break;
}
}
if (bGenerated)
{
continue;
}
else
{
lpDights[i] = nGen;
i++;
}
}
}
void CheckInputNum(LPCTSTR lpDigits,LPCTSTR lpGenDigits,LPTSTR lpResult,int nLenDigits,int nLenResult)
{
int nPosID = 0;
int nSameLetterID = nLenDigits;
TCHAR szTemp[256];

for (int i = 0;i < nLenDigits;i++)
{
if (lpGenDigits[i] == lpDigits[i])
{
nPosID++;
}
for (int j = 0;j < nLenDigits;j++)
{
if (lpGenDigits[i] == lpDigits[j])
{
nSameLetterID--;
}
}
}
wsprintf(szTemp,"%dA%dB",nPosID,nSameLetterID);
lstrcpyn(lpResult,szTemp,nLenResult + 1);

}
bool CheckInput(LPCTSTR lpDigits)
{
bool bGenerated = false;
int i = 0;
while(lpDigits[i] != '\0')
{
bGenerated = false;
if (i == 0)
{
i++;
continue;
}

for (int j = i - 1;j >= 0;j--)
{
if (lpDigits[j] == lpDigits[i])
{
return false;
break;
}
}
i++;
}
return true;
}

Answer 3

#include <iostream.h>
#include <time.h>
#include <stdlib.h>
void Checkout(char [],char [],int &,int &);
void Swap(char &a,char &b);
void main()
{
bool right=false;
char goon;
int times=0,perfect,nearly,init;
char guess[5],in[255],orig[10]={'0','1','2','3','4','5','6','7','8','9'};
srand((unsigned)time(NULL));
while (1)
{
for(int i=0;i<4;i++)
{
init=rand()%10;
Swap(orig[i],orig[init]);
}
for(i=0;i<4;i++)
guess[i]=orig[i];
guess[5]='\0';
right=false;
for(times=0;times<10 && !right;times++)
{
perfect=0;nearly=0;
cin>>in;
Checkout(guess,in,perfect,nearly);
cout<<perfect<<"A"<<nearly<<"B"<<endl;
if(perfect==4)
right=true;
}
if (right)
cout<<"You Get It!\n";
else
{
cout<<"Try Harder Next Time!\nThe number is ";
for (i=0;i<4;i++)
cout<<guess[i];
cout<<endl;
}
cout<<"Continue? y for yes,n for no ";
cin>>goon;
if(goon!='y' &&goon!='Y')
break;
}
}

void Checkout(char gn[4],char ck[4],int &p,int &n)
{
for (int i=0;i<4;i++)
{
if(ck[i]==gn[i])
p++;
else
{
for (int j=0;j<4;j++)
{
if(ck[i]==gn[j])
n++;
}
}
}
}

void Swap(char &a,char &b)
{
char temp;
temp=a;
a=b;
b=temp;
}本回答被提问者采纳

Answer 4

简单,看完就知道怎么做了
提示下:
产生随机数有个专用函树的,而且你这个程序产生的随机数没有排序的必要吧
将随机数放到数组里,将用户输入的数放到另一个数组里
利用循环加判断就可以搞定了
就提示这么多了,剩下的都是些语法问题了

Answer 5

很简单嘛