âan+2 - âan > c/âan+2
ç±ï¼1ï¼å¾å°ï¼an+2> = n+2 > 0.
æ以å¾å°ï¼n+2 - ân(n+2)>c;
n+2 - ân(n+2) = n+1 - ân(n+2) + 1 = 1 + 1 / [n+1 + ân(n+2)];
å½n->ï¼âæ¶ï¼n+2 - ân(n+2)->1,
èc< n+2 - ân(n+2),æ以cæ大=1ï¼
温馨提示:答案为网友推荐,仅供参考