x2+ (y-3√x2)=1

x2+ (y-3√x2)=1

√[(x+1)/(x-1)]-√[(x-1)/(x+1)]=3/2
令y=√[(x+1)/(x-1)]
y-1/y=3/2
y=2 y=-1/2(舍去)
∴√[(x+1)/(x-1)]=2
(x+1)/(x-1)=4
x+1=4x-4
x=5/3
检验:经检验x=5/3是方程的解
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