有一种“二十四点”的游戏,其游戏规则是这样的,任取四个1~13之间的正整数,将这四个数(每个数且只用一

进行加减乘除运算,使其结果等于24,现有四个正整数:2、2、3、11,运用上述规则,写出算式!!!!!!!!!!!!!!!

1: 2 × (3 - 2 + 11)
2: 2 × ((3 - 2) + 11)
3: 2 × (3 - (2 - 11))
4: 2 × (3 + 11 - 2)
5: 2 × ((3 + 11) - 2)
6: 2 × (3 + (11 - 2))
7: 2 × (11 - 2 + 3)
8: 2 × ((11 - 2) + 3)
9: 2 × (11 - (2 - 3))
10: 2 × (11 + 3 - 2)
11: 2 × ((11 + 3) - 2)
12: 2 × (11 + (3 - 2))
13: (3 - 2 + 11) × 2
14: ((3 - 2) + 11) × 2
15: (3 - (2 - 11)) × 2
16: (3 + 11 - 2) × 2
17: ((3 + 11) - 2) × 2
18: (3 + (11 - 2)) × 2
19: (11 - 2 + 3) × 2
20: ((11 - 2) + 3) × 2
21: (11 - (2 - 3)) × 2
22: (11 + 3 - 2) × 2
23: ((11 + 3) - 2) × 2
24: (11 + (3 - 2)) × 2
温馨提示:答案为网友推荐,仅供参考
第1个回答  2011-01-27
3-2=1
11+1=12
12X2=24
第2个回答  2011-01-27
[(3-2)+11]x2=24
相似回答