第2个回答 2011-01-31
1=1
-1+2=1
-1*2+3=1
1*2+3-4=1
1+2-(3+(4-5))=1
-1+2+3-(4+(5-6))=1
-1*2+3+4-(5+(6-7))=1
1*2+3-4+5-(6+(7-8))=1
1+2-(3+(4-5))+6-(7+(8-9))=1
-1+2+3-(4+(5-6))+7-(8+(9-10))=1
-1*2+3+4-(5+(6-7))+8-(9+(10-11))=1
1*2+3-4+5-(6+(7-8))+9-(10+(11-12))=1
………………
E+A-(B+(C-D))=1 E为初始四种情形