c语言 利用循环结构编写程序求1！+2！+……+100！的值

Question

如题所述

Answer 1

#include <stdio.h>
int main()
{ int i, j;
double item, sum;
sum = 0;
for(i = 1; i <= 100; i++)
{ item = 1;
for (j = 1; j <= i; j++)
item = item * j;
sum = sum + item;
}
printf("1! + 2! + 3! + … + 100! = %e\n", sum);
}