教科书印刷有问题,上面一条红线左端"a"应该是"2",然后应用三角积化和差公式,求前n项和时中间项全部抵消
2sin(x/2)*sin(kx)=cos(x/2-kx)-cos(x/2+kx)
=cos[(k-1/2)x]-cos[(k+1/2)x]
2sin(x/2)*Σ()=cos[(1/2)x]-cos[(3/2)x]
+cos[(3/2)x]-cos[(5/2)x]
+cos[(5/2)x]-cos[(7/2)x]
+……++cos[(n-1/2)x]-cos[(n+1/2)x]
=cos[(1/2)x]-cos[(n+1/2)x]
|2sin(x/2)*Σ()|<=2
Σ()<=1/|2sin(x/2)|
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