现有5,13,7,3将这4个数(每个数只用一次)进行加减乘除四则运算,使其结果等于24

如题所述

1: (5 × 13 + 7) ÷ 3
2: ((5 × 13) + 7) ÷ 3
3: (13 × 5 + 7) ÷ 3
4: ((13 × 5) + 7) ÷ 3
5: (7 + 5 × 13) ÷ 3
6: (7 + (5 × 13)) ÷ 3
7: (7 + 13 × 5) ÷ 3
8: (7 + (13 × 5)) ÷ 3
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