如题所述
Uab = 1 * 20 - 1 * 5 = 15 V
短路 ab 求 Isc :
i1 + Isc = 1
i1 = (5 * Isc + 5 * i1)/ 20
解得:
Isc = 0.75 A
Rab = Uab / Rab = 15 / 0.75 = 20Ω
I = Uab / (Rab + 10) = 15 / 30 = 0.5 A
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