c语言编程题，计算1+2！+3！＋4！＋······＋10！的值怎么编程呀？？具体的步骤。。。。。

Question

如题所述

Answer 1

您看满意否，满意请采纳
#include <stdio.h>

void main ()
{
int n = 1, i;
int sum = 0;
for (i = 1; i <= 10; ++i)
{
n *= i;
sum += n;
}
printf("结果为：%d", sum);
}

Answer 2

#include <stdio.h>
void main ()
{
int i,n,j,sum=0;
int m;
scanf("%d",&n);
for(i=1;i<=n;++i)
{
m=1;
for(j=1;j<=i;++j)
m*=j;
sum=sum+m;
}
printf("1!+2!+...n!=%d\n",sum);
}

Answer 3

#include <stdio.h>
main()
{
int i,j;
int s=0;
for(i=1;i<=10;i++)
{
int s1=1;
for(j=1;j<=i;j++)
s1=s1*j;
s=s+s1;
}
printf("%d",s);
}

Answer 4

#include <stdio.h>

int main()
{
int sum = 0;
int step = 1;
int i;
for(i=1;i<=10;i++)
{
step *= i;
sum += step;
}
printf("Answer = %d\n",sum);
}本回答被提问者采纳