编程求整数序列和要求程序运行时输入正整数n,求1+3+5…+2n–1的值并输出
#include <stdio.h>
int main()
{
int i,n,sum;
scanf("%d",&n);
for(i=1,sum=0;i<=n;++i)
sum+=2*i-1;
printf("%d\n",sum);
return 0;
}
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求数列:a^2–1,a^3–3,a^4–5,a^n+1–(2n–1),…前n项的和答:若a=1时原式=1^2+a1^3+1^4+,,,+1^n+1-(1+3+5+(2n-1))=n-n^2 若a≠0且a≠1时原式=a^2+a^3+a^4+,,,+a^n+1-(1+3+5+(2n-1))=【a^2-a^2(a^n)】/(1-a)-n^2