等差数列an的前n项和为Sn,等比数列bn,a1=1,a4=7,b1=a1+1,b4=a3+1,(1)求证(1/s1)+(1/s2)+···+(1/sn)<2.

Question

(2)cn=an/bn,求cn的最大值
上面的b4=a3+1打错了，应该是b4=a8+1

Answer 1