我在matlab/simulink环境下搭建了一个框图,其中一部分输出为一个2*1的矩阵,然后我编写了一个s函数求解输出量,输入量分别为矩阵中的两个值,输出量为2*2的矩阵,但是在运行时系统报错说我未定义输出量u1,u2。请大大帮忙看看我该如何定义这种输出量。贴出s函数的m文件。
function [sys,x0,str,ts,simStateCompliance] = sfun1(t,x,u,flag)
switch flag,
case 0,
[sys,x0,str,ts,simStateCompliance]=mdlInitializeSizes;
case 1,
sys=mdlDerivatives(t,x,u);
case 2,
sys=mdlUpdate(t,x,u);
case 3,
sys=mdlOutputs(t,x,u);
case 4,
sys=mdlGetTimeOfNextVarHit(t,x,u);
case 9,
sys=mdlTerminate(t,x,u);
otherwise
DAStudio.error('Simulink:blocks:unhandledFlag', num2str(flag));
end
function [sys,x0,str,ts,simStateCompliance]=mdlInitializeSizes
sizes = simsizes;
sizes.NumContStates = 2;
sizes.NumDiscStates = 0;
sizes.NumOutputs = 2;
sizes.NumInputs = 2;
sizes.DirFeedthrough = 1;
sizes.NumSampleTimes = 1; % at least one sample time is needed
sys = simsizes(sizes);
x0 = [];
str = [];
ts = [0 0];
simStateCompliance = 'UnknownSimState';
function sys=mdlUpdata(t,x,u)
sys = []
function sys=mdlOutputs(t,x,u1,u2)
c=0.0361;
p=2.9763;
l=0.7;
y1=(sin(p*l)-sinh(p*l)-(sinh(p*l)+sin(p*l))/(cosh(p*l)+cos(p*l))*(cos(p*l)-cosh(p*l)))*c;
fun1(1,1)=-sin(u1)-y1*(u2).*cos(u1);
fun1(2,1)=-sin(u1);
fun1(1,2)=cos(u1)-y1*(u2).*sin(u1);
fun1(2,2)=cos(u1);
sfun1=fun1^-1;
sys = sfun1
function sys=mdlTerminate(t,x,u)
sys = [];
朋友,那篇问题我也看过,但是我们的问题就是不一样的,你直接粘贴过来也不适合啊...