如题所述
左下、右上是两个相互独立的闭合回路:
U1 = 8/2 = 4 V
Uab = U1 + 0.5U1 * 4 = 12 V
节点电压法:
(1/2 + 1/2 + 1/4) * U1 = 8/2 - 0.5 * U1
U1 = 16/7 V
Isc = 0.5 * U1 + U1/4 = 12/7 A
Rab = Uab / Isc = 7Ω
RL = 7Ω 时获得最大功率:
Pmax = 6 * 6 / 7 = 5.14 W
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