通达信指标能转成同花顺指标吗?跪求高手

Question

代码：
DIFF:=( EMA(CLOSE,7) - EMA(CLOSE,19)),COLORWHITE;
DEA:=EMA(DIFF,9),COLORF00FF0 ;
MACD:=0.90*(DIFF-DEA), COLORSTICK;
TJ:=(DIFF>=DEA);
TJ1:=(DIFF>=0);
{STICKLINE(TJ,H,L,0,0),COLORYELLOW;}
STICKLINE(TJ,O,C,3,1),COLORYELLOW;
STICKLINE(TJ1 AND TJ,H,L,0,0),COLORF00FF0;
STICKLINE(TJ1 AND TJ,O,C,3,1),COLORF00FF0;
STICKLINE(DIFF<DEA,H,L,0,0),COLORF0F000;
STICKLINE(DIFF<DEA,O,C,3,0),COLORF0F000;
VAR1:=(CLOSE*2 HIGH LOW)/4;
SK:= EMA(VAR1,13)-EMA(VAR1,73);
SD:= EMA(SK,2);
{DRAWTEXT((CROSS(SK,SD) AND SK<-0.04 AND (C-REF(C,1))/REF(C,1)>=0.03) OR (CROSS(SK,SD)
AND SK<=-0.14 ) OR (CROSS(SK,SD) AND SK<=0.05 AND (V/MA(V,5)>2 OR C/REF(C,1)>0.035)) ,
L*0.99,'短线'),COLORRED;}
{STICKLINE((CROSS(SK,SD) AND SK<-0.04 AND (C-REF(C,1))/REF(C,1)>=0.03) OR (CROSS(SK,SD)
AND SK<=-0.14 ) OR (CROSS(SK,SD) AND SK<=0.05 AND (V/MA(V,5)>2 OR C/REF(C,1)>0.035)),
H,L,0,0),COLORRED;}
STICKLINE((CROSS(SK,SD) AND SK<-0.04 AND (C-REF(C,1))/REF(C,1)>=0.03) OR (CROSS(SK,SD)
AND SK<=-0.14 ) OR (CROSS(SK,SD) AND SK<=0.05 AND (V/MA(V,5)>2 OR C/REF(C,1)>0.035)),
O,C,3,0),LINETHICK3,COLORRED;
二号线:=EMA(C,25),COLORWHITE,LINETHICK2;
八号线:=EMA(C,99),POINTDOT,LINETHICK2,COLORWHITE;
一号线:=EMA(CLOSE,144),POINTDOT,LINETHICK2,COLOR0000FF;
三号线:=EMA(C,318),COLOR0000FF,LINETHICK2;
四黑马线:=EMA(C,453),CIRCLEDOT,LINETHICK1,COLOR428899;
SS:=CROSS(二号线,八号线) AND C>1.5 AND C>REF(C,1.5) AND C/REF(C,1.5)>=0.98
OR CROSS(二号线,三号线) AND C>1.5 AND C>REF(C,1.5) AND C/REF(C,1.5)>=0.98
OR CROSS(二号线,一号线) AND C>1.5 AND C>REF(C,1.5) AND C/REF(C,1.5)>=0.98{AND CROSS
(二号线,三号线)};
DRAWICON(SS,L-0.04,1);
DD:=CROSS(八号线,一号线) AND C>1.5 AND C>REF(C,1.5) AND C/REF(C,1.5)>=0.98
OR CROSS(八号线,四黑马线) AND C>1.5 AND C>REF(C,1.5) AND C/REF(C,1.5)>=0.98
OR CROSS(八号线,三号线) AND C>1.5 AND C>REF(C,1.5) AND C/REF(C,1.5)>=0.98
OR CROSS(八号线,三号线) AND C>1.5 AND C>REF(C,1.5) AND C/REF(C,1.5)>=0.98 AND CROSS
(二号线,四黑马线);
{DD:=CROSS(二号线,四黑马线);};

以上是通达信的，转为同花顺指标，跪求了

Answer 1

两种看盘软件大部的公式函数是通用的，但还是存在着不同的地方，因此不能。追问

是的，大写能修改下吗

追答

我一直用的是通达信，偶尔用一下大智慧或同花顺，所以我给不了你确切答案。实在不行你在网上下载两看盘软件函数大全对照查找一下，也许能解决问题