f(x)=e^x
[f(x+â³x)-f(x)]/â³
=[e^(x+â³x)-e^x]/â³x
=e^x[e^â³x-1]/â³x
e^â³x,ç±æ³°åå
¬å¼å±å¼æe^â³x=1+â³x+â³x^2/2!+â³x^3/3!+â¦â¦æ以[f(x+â³x)-f(x)]/â³x=e^x(1+â³x+â³x^2/2!+â³x^3/3!+â¦â¦-1)/â³x=e^x(â³x+â³x^2/2!+â³x^3/3!+â¦â¦)/â³x=e^x(1+â³x/2!+â³x^2/3!+â¦â¦)â³xè¶äº0ï¼åæé=e^x
æ以(e^x)'=e^x
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