大学电路题，求详细解答，谢谢，正确必采纳

Question

如题所述

Answer 1

V1 = Us = 15

(1/R2 + 1/R3 + 1/R4) * V2 - V1/R2 - V3/R3 = 0

2V2 - V3 = 10                          (1)

(1/R3 + 1/R5) * V3 - V2/R3 = Is - Ucs/R5

5V3 - 4V2 = 8 - Ucs                 (2)

I1 = (V1 - V2) / R2                   (3)

Ucs = 2 I1                                (4)

解得：

V2 = - 10.3V

V3 = - 30.6V

I1 = 8.433A

Is1 = Is + I1

   = 9.433A

P_Us = - Is1 * Us = -  141.5W

P_Is = (V1 - V3) * 1A = 45.6W

电压源发出功率 141.5瓦，电流源吸收功率 45.6瓦 。

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