用C语言编写这样一个小程序：随便输入二个日期求出其时间段。（哭求）

Question

如2002年2月7日和2007年3月17日求出其总天数

Answer 1

#include "stdio.h"

void chang(int *a,int *b)
{
int temp;
temp=*a;
*a=*b;
*b=temp;
}

int isR(int year)
{
if(year%4==0&&(year%400==0||year%100!=0)) return 1;
return 0;
}

int check(int *y1,int *m1,int *d1,int *y2,int *m2,int *d2)
{
int mon1[13]={0,31,28,31,30,31,30,31,31,30,31,30,31};
int mon2[13]={0,31,28,31,30,31,30,31,31,30,31,30,31};
if(isR(*y1)) mon1[2] = 29;
if(isR(*y2)) mon2[2] = 29;
if(*m1 <= 0 || *m1 > 12 || *m2 <= 0 || *m2 >12 || *d1 <= 0 || *d1 > 31)
return 0;
if(*d1>mon1[*m1]||*d2>mon2[*m2]) return 0;
if(*y1 > *y2)
{
chang(y1,y2);
chang(m1,m2);
chang(d1,d2);
}
return 1;
}

int TTD(int year,int month,int day)
{
int mon[13]={0,31,28,31,30,31,30,31,31,30,31,30,31};
int sum=0;
int i=1;
if(month <= 0 || month > 12 || day > 31 || day <= 0 )
return 0;
if(day > mon[month]) return 0;
if(isR(year)) mon[2] = 29;
for(;i<=month;i++)
sum+=mon[i-1];
sum+=day;
return sum;
}

int main()
{
int y1,m1,d1,y2,m2,d2;
long sum=0;
printf("请输入日期1(年-月-日):");
scanf("%d-%d-%d",&y1,&m1,&d1);
printf("请输入日期2(年-月-日):");
scanf("%d-%d-%d",&y2,&m2,&d2);
if(!check(&y1,&m1,&d1,&y2,&m2,&d2))
{
printf("您输入的日期有误，请检查！"); return -1;
}
for(int i=y1;i<y2;i++)
if(isR(i)) sum+=366;
else sum+=365;
sum-=TTD(y1,m1,d1);
sum+=TTD(y2,m2,d2);
printf("共%ld天\n",abs(sum));
return 0;
}

Answer 2

#include
"stdio.h"
void
chang(int
*a,int
*b)
{
int
temp;
temp=*a;
*a=*b;
*b=temp;
}
int
isR(int
year)
{
if(year%4==0&&(year%400==0||year%100!=0))
return
1;
return
0;
}
int
check(int
*y1,int
*m1,int
*d1,int
*y2,int
*m2,int
*d2)
{
int
mon1[13]={0,31,28,31,30,31,30,31,31,30,31,30,31};
int
mon2[13]={0,31,28,31,30,31,30,31,31,30,31,30,31};
if(isR(*y1))
mon1[2]
=
29;
if(isR(*y2))
mon2[2]
=
29;
if(*m1
<=
0
||
*m1
>
12
||
*m2
<=
0
||
*m2
>12
||
*d1
<=
0
||
*d1
>
31)
return
0;
if(*d1>mon1[*m1]||*d2>mon2[*m2])
return
0;
if(*y1
>
*y2)
{
chang(y1,y2);
chang(m1,m2);
chang(d1,d2);
}
return
1;
}
int
TTD(int
year,int
month,int
day)
{
int
mon[13]={0,31,28,31,30,31,30,31,31,30,31,30,31};
int
sum=0;
int
i=1;
if(month
<=
0
||
month
>
12
||
day
>
31
||
day
<=
0
)
return
0;
if(day
>
mon[month])
return
0;
if(isR(year))
mon[2]
=
29;
for(;i<=month;i++)
sum+=mon[i-1];
sum+=day;
return
sum;
}
int
main()
{
int
y1,m1,d1,y2,m2,d2;
long
sum=0;
printf("请输入日期1(年-月-日):");
scanf("%d-%d-%d",&y1,&m1,&d1);
printf("请输入日期2(年-月-日):");
scanf("%d-%d-%d",&y2,&m2,&d2);
if(!check(&y1,&m1,&d1,&y2,&m2,&d2))
{
printf("您输入的日期有误，请检查!");
return
-1;
}
for(int
i=y1;i<y2;i++)
if(isR(i))
sum+=366;
else
sum+=365;
sum-=TTD(y1,m1,d1);
sum+=TTD(y2,m2,d2);
printf("共%ld天\n",abs(sum));
return
0;
}