无锡哪里有手工活可以带回家做的?

Question

无锡哪里有手工活可以带回家做的? 要真的,不要骗人的!
网上和报纸上也看到了不少,要交压金的,但不知道是不是真的?

Answer 1

无锡解放西路159号有手工活，就是在规定时间内完成退回保证金，工艺品很不错

Answer 2

1/[x(1 x)(1 x x^2)]≡A/x B/(x 1) (Cx D)/(x^2 x 1)

=>

1≡A(1 x)(1 x x^2) Bx(1 x x^2) (Cx D)x(1 x)

x=0，=>A=1/3

x=-1，=>B=-1

A B C=0

1/3-1 C=0

C=-2/3

x=1

6A 3B 2(C D)=1

2-3-4/3 2D=1

D=5/3

1/[x(1 x)(1 x x^2)]

≡(1/3)(1/x)-1/(x 1) (1/3)[(-2x 5)/(x^2 x 1)]

∫dx/[x(1 x)(1 x x^2)]

=∫(1/3)(1/x)-1/(x 1) (1/3)[(-2x 5)/(x^2 x 1)dx

=(1/3)ln|x|-ln|x 1| (1/3)∫(-2x 5)/(x^2 x 1)dx

=(1/3)ln|x|-ln|x 1|-(1/3)∫(2x 1)/(x^2 x 1)dx 2∫dx/(x^2 x 1)dx

=(1/3)ln|x|-ln|x 1|-(1/3)ln|x^2 x 1| 2∫dx/(x^2 x 1)dx

=(1/3)ln|x|-ln|x 1|-(1/3)ln|x^2 x 1| (4√3/3)arctan[(2x 1)/√3] C

x^2 x 1=(x 1/2)^2 3/4

x 1/2=(√3/2)tanu

dx=(√3/2)(secu)^2du

∫dx/(x^2 x 1)

=∫(√3/2)(secu)^2du/[(3/4)(secu)^2]

=(2√3/3)u C

=(2√3/3)arctan[(2x 1)/√3] C

Answer 3

原式=∫[x 1-2√(x 1) 1]/xdx

=∫(1 2/x-2√(x 1)/x]dx

a=√(x 1)

x=a2-1

dx=2ada

所以∫√(x 1)/xdx

=∫2a2da/(a2-1)

=∫2 [2/(a2-1)]da

=∫[2 1/(a-1)-1/(a 1)]da

=2a ln|a-1|-ln|a 1|

所以原式=x 2ln|x|-4√(x 1)-2ln|√(x 1)-1| 2ln|√(x 1) 1| C