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log4除以log2
log4
^2n怎么化成n/2,求详解
答:
换底公式
log4
(2^n)=lg2^n/lg4=nlg2/2lg2=n/2
log2
^4等于多少,帮忙看一下,我忘了
答:
log<2> 4 =log<2> 2^2 =
2log
<2>2 =2
log4
(1\2)+log8(4)
答:
log4
(1\2)+log8(4)=1/
2log2
(1\2)+1/3log2(4)=-1/2+1/3x2 =-1/2+2/3 =1/6
log4
(a 2)=1,计算loga4
log2
(a-1)
答:
log₂(a 2)=1,a=2,loga4
log2
(a-1)=log₂
4log
₂1=2×0=0
log4
^(2-X)=
log2
^(X-1)-1 我是换成 1/
2log
x^(2-x)=log2^(x-1)-log...
答:
log4
^(2-x)=
log2
^(x-1)-1 1/2*log2(2-x)=log2(x-1)-log2(2)即log2√(2-x)log2[(x-1)/2]所以√(2-x)=[(x-1)/2 两边平方化简后得到x^2+2x-7=0 解得x=-1+2√2或x=-1-2√2 又2-x>0,x-1>0 所以1 ...
运用对数换底公式化简
log2
(3)*log3(4)*
log4
(5)*log5(2),要过程
答:
log2
(3)*log3(4)*
log4
(5)*log5(2)=log2(3)*log3(2^2)*log2^2(5)*log5(2)=log2(3)*
2log
3(2)*1/2 * log2(5)*log5(2) (2与1/2约分了)=log2(3)*1/log2(3) * log2(5) * 1/log2(5)=1
函数
log2
(4x)乘
log4
(4/x^2)>=2
答:
(
log2
(4)+log2(x))*(
log4
(4)-log4(x^2))>=2 (2+log2(x))*(1-log2(x))>=2 2-2*log2(x)+log2(x)-(log2(x))^2>=2 -log2(x)-(log2(x))^2>=0 log2(x)+(log2(x))^2<=0 log2(x)*(1+log2(x))<=0 log2(x)*log2(2x)<=0 在数轴上标根、穿线,...
高一两题对数计算题求解答
答:
= [ (log6【6/3】)^2 + log6【2】* log6【18】] ÷ [
2log
6【2】]= [ (log6【2】) + log6【18】] ÷ 2 = [ (log6【2*18】] ÷ 2 = [ (log6【6^2】] ÷ 2 = 2 ÷ 2 = 1 (
log2
【5】+
log4
【125】)* log3【2】/ log√3【5】= ( lg5 / lg2+ lg...
log2
(log3(
log4
的对数a))=log3(log4(log2的对数b))则a/b的值为?_百度...
答:
令
log2
(log3(
log4
的对数a))=log3(log4(log2的对数b)=k 那么log2(log3(log4的对数a)]=k log3(log4的对数a)=2^k log4的对数a=3^(2^k)a=4^[3^(2^k)]同理,b=2^[4^(3^k)]
log2
m<
log4
(m 2),再简化成怎样呢?
答:
对数有意义,m>0,m+2>0 m>0
log2
(m)<
log4
(m+2)log4(m²)>log4(m+2)m²>m+2 m²-m-2>0 (m+1)(m-2)>0 m<-1或m>2,又m>0,因此m>2 m的取值范围为(2,+∞)
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