int choose(int score[], int N, int below[]) { int sum = 0, i, number = 0; for (i = 0; i < N; i++) { sum = sum + score[i]; } for (i = 0; i < N; i++) { if (score[i] * N < sum) { below[number] = score[i]; number++; } } return number;}
第2个回答 2020-03-16
#include<iostream> #define a 10.2//定义a 的值为10.2 using namespace std; int main() { float x,y; cin>>x; y=3*a*x*x+4*a*x-1; cout<<y; return 0; }本回答被提问者和网友采纳