tanx 求导数是什么

Question

如题所述

Answer 1

(tanx)' = 1/(cosx)^2 = (secx)^2

(tanx)'
= (sinx/cosx)'
= [cosx*cosx - sinx(-sinx)]/(cosx)^2
= 1/(cosx)^2
= (secx)^2本回答被提问者采纳

Answer 2

结果为2÷sin2x=2csc2x

Answer 3

(sinx/cosx)'== [cosx*cosx - sinx(-sinx)]/(cosx)^2
= 1/(cosx)^2
= (secx)^2本回答被网友采纳