C程序设计题,简单计算器,编写一个程序,计算表达式 date1 op date2...答:include <stdio.h> void main(){ int data1,data2;char op;scanf("%d%c%d",&data1,&op,&data2);if(op=='+')printf("%d+%d=%d\n",data1,data2,data1+data2);if(op=='-')printf("%d-%d=%d\n",data1,data2,data1-data2);if(op=='*')printf("%d*%d=%d\n",data1,...