一个九位数,前i位是i的倍数(i从1到9),写出结果和C++实现的代码_百度知 ...答:上面那个循环次数太多 include<iostream.h> int main(){ long a1,a2,a3,a4,a5,a6,a7,a8,a9;long m;cout<<"计算结果"<<endl;for(a1=1;a1<10;a1++){ for(a2=1;a2<10;a2++){ if(a2==a1)continue;m=a1*10+a2;if(m%2!=0)continue;for(a3=1;a3<10;a3++){ if(a3==a1||a3...