C语言编程:输入两个正整数a和n,求a+aa+…+aa…a(n个a)之和答:return an;} //求a+aa+aaa+...+an的和 int f2(int a,int n){ int s=0;for(int i=1;i<=n;i++){ s+=f1(a,i);} return s;} int main(){ int a,n;scanf("%d %d",&a,&n);printf("第%d项的值为:%d\n",n,f1(a,n));printf("所有n项之和:%d\n",f2(a,n))...
...之和输入2个正整数a和n,求a+aa+aaa+aa…a(n个a)之和。答:h>int main(void){ int a,n,i,sum,z=0,aa=0; printf("Input a,n: "); scanf("%d,%d",&a,&n); sum=0; for(i=1;i<=n;i++){ sum=10*sum+a; //这里循环节你错了 z=z+sum; } printf("s=%d",z); return 0; } ...