将一个数组中的值按逆序重新存放。例如,原来顺序为8,6,5,4,1。要求...答:{ char arr[10] = { 1, 2, 3, 4, 5, 6, 7, 8, 9, 0 };int i = 0;int len = sizeof(arr) / sizeof(arr[0]);int tmp = 0;for (i = 0; i < (len/2); ++i) //进行len/2次交换 { tmp = arr[9 - i];arr[9 - i] = arr[i];arr[i] = tmp;} for...