有一天平有六种砝码,重1,2,3,5,10,20克,每种砝码各有5,3,2,2,1,1...答:define NUM 6 //砝码的种类 define MAX 58 //最大能称量的重量+1 int main(int argc, char **argv) { int m[NUM] = { 1,2,3,5,10,20 }, n[NUM] = { 5,3,2,2,1,1 }, i[NUM];int flag[MAX] = { 0 };for (i[0] = 0; i[0] <= n[0]; i[0]++)for ...